5[f+2]=2[3-f]

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Solution for 5[f+2]=2[3-f] equation:


Simplifying
5[f + 2] = 2[3 + -1f]

Reorder the terms:
5[2 + f] = 2[3 + -1f]
[2 * 5 + f * 5] = 2[3 + -1f]
[10 + 5f] = 2[3 + -1f]
10 + 5f = [3 * 2 + -1f * 2]
10 + 5f = [6 + -2f]

Solving
10 + 5f = 6 + -2f

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Add '2f' to each side of the equation.
10 + 5f + 2f = 6 + -2f + 2f

Combine like terms: 5f + 2f = 7f
10 + 7f = 6 + -2f + 2f

Combine like terms: -2f + 2f = 0
10 + 7f = 6 + 0
10 + 7f = 6

Add '-10' to each side of the equation.
10 + -10 + 7f = 6 + -10

Combine like terms: 10 + -10 = 0
0 + 7f = 6 + -10
7f = 6 + -10

Combine like terms: 6 + -10 = -4
7f = -4

Divide each side by '7'.
f = -0.5714285714

Simplifying
f = -0.5714285714

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